-2(n-4)+12=2n+40

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Solution for -2(n-4)+12=2n+40 equation: 



-2(n-4)+12=2n+40

We move all terms to the left:

-2(n-4)+12-(2n+40)=0

We multiply parentheses

-2n-(2n+40)+8+12=0

We get rid of parentheses

-2n-2n-40+8+12=0

We add all the numbers together, and all the variables

-4n-20=0

We move all terms containing n to the left, all other terms to the right

-4n=20

n=20/-4

n=-5

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