-2(j-3)=3j+6

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Solution for -2(j-3)=3j+6 equation: 



-2(j-3)=3j+6

We move all terms to the left:

-2(j-3)-(3j+6)=0

We multiply parentheses

-2j-(3j+6)+6=0

We get rid of parentheses

-2j-3j-6+6=0

We add all the numbers together, and all the variables

-5j=0

j=0/-5

j=0

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