-2(h+12)+3(2h-4)=40

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Solution for -2(h+12)+3(2h-4)=40 equation: 



-2(h+12)+3(2h-4)=40

We move all terms to the left:

-2(h+12)+3(2h-4)-(40)=0

We multiply parentheses

-2h+6h-24-12-40=0

We add all the numbers together, and all the variables

4h-76=0

We move all terms containing h to the left, all other terms to the right

4h=76

h=76/4

h=19

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