-2(d-3)+5d=4(d+5)

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Solution for -2(d-3)+5d=4(d+5) equation: 



-2(d-3)+5d=4(d+5)

We move all terms to the left:

-2(d-3)+5d-(4(d+5))=0

We add all the numbers together, and all the variables

5d-2(d-3)-(4(d+5))=0

We multiply parentheses

5d-2d-(4(d+5))+6=0



We calculate terms in parentheses: -(4(d+5)), so:

4(d+5)

We multiply parentheses

4d+20

Back to the equation:

-(4d+20)



We add all the numbers together, and all the variables

3d-(4d+20)+6=0

We get rid of parentheses

3d-4d-20+6=0

We add all the numbers together, and all the variables

-1d-14=0

We move all terms containing d to the left, all other terms to the right

-d=14

d=14/-1

d=-14

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