-2(b-4)+3(b+2)=-27

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Solution for -2(b-4)+3(b+2)=-27 equation:


Simplifying
-2(b + -4) + 3(b + 2) = -27

Reorder the terms:
-2(-4 + b) + 3(b + 2) = -27
(-4 * -2 + b * -2) + 3(b + 2) = -27
(8 + -2b) + 3(b + 2) = -27

Reorder the terms:
8 + -2b + 3(2 + b) = -27
8 + -2b + (2 * 3 + b * 3) = -27
8 + -2b + (6 + 3b) = -27

Reorder the terms:
8 + 6 + -2b + 3b = -27

Combine like terms: 8 + 6 = 14
14 + -2b + 3b = -27

Combine like terms: -2b + 3b = 1b
14 + 1b = -27

Solving
14 + 1b = -27

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 1b = -27 + -14

Combine like terms: 14 + -14 = 0
0 + 1b = -27 + -14
1b = -27 + -14

Combine like terms: -27 + -14 = -41
1b = -41

Divide each side by '1'.
b = -41

Simplifying
b = -41

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