-2(8x-7)+(3x-2)=4x-2(3+x)

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Solution for -2(8x-7)+(3x-2)=4x-2(3+x) equation: 



-2(8x-7)+(3x-2)=4x-2(3+x)

We move all terms to the left:

-2(8x-7)+(3x-2)-(4x-2(3+x))=0

We add all the numbers together, and all the variables

-2(8x-7)+(3x-2)-(4x-2(x+3))=0

We multiply parentheses

-16x+(3x-2)-(4x-2(x+3))+14=0

We get rid of parentheses

-16x+3x-(4x-2(x+3))-2+14=0



We calculate terms in parentheses: -(4x-2(x+3)), so:

4x-2(x+3)

We multiply parentheses

4x-2x-6

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

-13x-(2x-6)+12=0

We get rid of parentheses

-13x-2x+6+12=0

We add all the numbers together, and all the variables

-15x+18=0

We move all terms containing x to the left, all other terms to the right

-15x=-18

x=-18/-15

x=1+1/5

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