-2(8v-4)+4v=6(v+2)

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Solution for -2(8v-4)+4v=6(v+2) equation: 



-2(8v-4)+4v=6(v+2)

We move all terms to the left:

-2(8v-4)+4v-(6(v+2))=0

We add all the numbers together, and all the variables

4v-2(8v-4)-(6(v+2))=0

We multiply parentheses

4v-16v-(6(v+2))+8=0



We calculate terms in parentheses: -(6(v+2)), so:

6(v+2)

We multiply parentheses

6v+12

Back to the equation:

-(6v+12)



We add all the numbers together, and all the variables

-12v-(6v+12)+8=0

We get rid of parentheses

-12v-6v-12+8=0

We add all the numbers together, and all the variables

-18v-4=0

We move all terms containing v to the left, all other terms to the right

-18v=4

v=4/-18

v=-2/9

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