-2(7-10y)=3(10y+12)

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Solution for -2(7-10y)=3(10y+12) equation: 



-2(7-10y)=3(10y+12)

We move all terms to the left:

-2(7-10y)-(3(10y+12))=0

We add all the numbers together, and all the variables

-2(-10y+7)-(3(10y+12))=0

We multiply parentheses

20y-(3(10y+12))-14=0



We calculate terms in parentheses: -(3(10y+12)), so:

3(10y+12)

We multiply parentheses

30y+36

Back to the equation:

-(30y+36)



We get rid of parentheses

20y-30y-36-14=0

We add all the numbers together, and all the variables

-10y-50=0

We move all terms containing y to the left, all other terms to the right

-10y=50

y=50/-10

y=-5

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