-2(6y-5)-y=4(y-2)

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Solution for -2(6y-5)-y=4(y-2) equation: 



-2(6y-5)-y=4(y-2)

We move all terms to the left:

-2(6y-5)-y-(4(y-2))=0

We add all the numbers together, and all the variables

-1y-2(6y-5)-(4(y-2))=0

We multiply parentheses

-1y-12y-(4(y-2))+10=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We add all the numbers together, and all the variables

-13y-(4y-8)+10=0

We get rid of parentheses

-13y-4y+8+10=0

We add all the numbers together, and all the variables

-17y+18=0

We move all terms containing y to the left, all other terms to the right

-17y=-18

y=-18/-17

y=1+1/17

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