-2(6y-5)+9y=3(y+6)

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Solution for -2(6y-5)+9y=3(y+6) equation: 



-2(6y-5)+9y=3(y+6)

We move all terms to the left:

-2(6y-5)+9y-(3(y+6))=0

We add all the numbers together, and all the variables

9y-2(6y-5)-(3(y+6))=0

We multiply parentheses

9y-12y-(3(y+6))+10=0



We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)



We add all the numbers together, and all the variables

-3y-(3y+18)+10=0

We get rid of parentheses

-3y-3y-18+10=0

We add all the numbers together, and all the variables

-6y-8=0

We move all terms containing y to the left, all other terms to the right

-6y=8

y=8/-6

y=-1+1/3

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