-2(6y-3)+8y=2(y+4)

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Solution for -2(6y-3)+8y=2(y+4) equation: 



-2(6y-3)+8y=2(y+4)

We move all terms to the left:

-2(6y-3)+8y-(2(y+4))=0

We add all the numbers together, and all the variables

8y-2(6y-3)-(2(y+4))=0

We multiply parentheses

8y-12y-(2(y+4))+6=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We add all the numbers together, and all the variables

-4y-(2y+8)+6=0

We get rid of parentheses

-4y-2y-8+6=0

We add all the numbers together, and all the variables

-6y-2=0

We move all terms containing y to the left, all other terms to the right

-6y=2

y=2/-6

y=-1/3

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