-2(6y-2)-y=-2(y-5)

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Solution for -2(6y-2)-y=-2(y-5) equation: 



-2(6y-2)-y=-2(y-5)

We move all terms to the left:

-2(6y-2)-y-(-2(y-5))=0

We add all the numbers together, and all the variables

-1y-2(6y-2)-(-2(y-5))=0

We multiply parentheses

-1y-12y-(-2(y-5))+4=0



We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We add all the numbers together, and all the variables

-13y-(-2y+10)+4=0

We get rid of parentheses

-13y+2y-10+4=0

We add all the numbers together, and all the variables

-11y-6=0

We move all terms containing y to the left, all other terms to the right

-11y=6

y=6/-11

y=-6/11

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