-2(6y-2)+9y=1+3(2y-1)

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Solution for -2(6y-2)+9y=1+3(2y-1) equation: 



-2(6y-2)+9y=1+3(2y-1)

We move all terms to the left:

-2(6y-2)+9y-(1+3(2y-1))=0

We add all the numbers together, and all the variables

9y-2(6y-2)-(1+3(2y-1))=0

We multiply parentheses

9y-12y-(1+3(2y-1))+4=0



We calculate terms in parentheses: -(1+3(2y-1)), so:

1+3(2y-1)

determiningTheFunctionDomain
3(2y-1)+1

We multiply parentheses

6y-3+1

We add all the numbers together, and all the variables

6y-2

Back to the equation:

-(6y-2)



We add all the numbers together, and all the variables

-3y-(6y-2)+4=0

We get rid of parentheses

-3y-6y+2+4=0

We add all the numbers together, and all the variables

-9y+6=0

We move all terms containing y to the left, all other terms to the right

-9y=-6

y=-6/-9

y=2/3

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