-2(6x+8)+7x=3x-2+(12+4x)

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Solution for -2(6x+8)+7x=3x-2+(12+4x) equation: 



-2(6x+8)+7x=3x-2+(12+4x)

We move all terms to the left:

-2(6x+8)+7x-(3x-2+(12+4x))=0

We add all the numbers together, and all the variables

-2(6x+8)+7x-(3x-2+(4x+12))=0

We add all the numbers together, and all the variables

7x-2(6x+8)-(3x-2+(4x+12))=0

We multiply parentheses

7x-12x-(3x-2+(4x+12))-16=0



We calculate terms in parentheses: -(3x-2+(4x+12)), so:

3x-2+(4x+12)

determiningTheFunctionDomain
3x+(4x+12)-2

We get rid of parentheses

3x+4x+12-2

We add all the numbers together, and all the variables

7x+10

Back to the equation:

-(7x+10)



We add all the numbers together, and all the variables

-5x-(7x+10)-16=0

We get rid of parentheses

-5x-7x-10-16=0

We add all the numbers together, and all the variables

-12x-26=0

We move all terms containing x to the left, all other terms to the right

-12x=26

x=26/-12

x=-2+1/6

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