-2(6v-2)+4v=2(v+5)

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Solution for -2(6v-2)+4v=2(v+5) equation: 



-2(6v-2)+4v=2(v+5)

We move all terms to the left:

-2(6v-2)+4v-(2(v+5))=0

We add all the numbers together, and all the variables

4v-2(6v-2)-(2(v+5))=0

We multiply parentheses

4v-12v-(2(v+5))+4=0



We calculate terms in parentheses: -(2(v+5)), so:

2(v+5)

We multiply parentheses

2v+10

Back to the equation:

-(2v+10)



We add all the numbers together, and all the variables

-8v-(2v+10)+4=0

We get rid of parentheses

-8v-2v-10+4=0

We add all the numbers together, and all the variables

-10v-6=0

We move all terms containing v to the left, all other terms to the right

-10v=6

v=6/-10

v=-3/5

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