-2(6v-2)+1=33+2v

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Solution for -2(6v-2)+1=33+2v equation: 



-2(6v-2)+1=33+2v

We move all terms to the left:

-2(6v-2)+1-(33+2v)=0

We add all the numbers together, and all the variables

-2(6v-2)-(2v+33)+1=0

We multiply parentheses

-12v-(2v+33)+4+1=0

We get rid of parentheses

-12v-2v-33+4+1=0

We add all the numbers together, and all the variables

-14v-28=0

We move all terms containing v to the left, all other terms to the right

-14v=28

v=28/-14

v=-2

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