-2(6u-5)+3u=3(u+6)

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Solution for -2(6u-5)+3u=3(u+6) equation: 



-2(6u-5)+3u=3(u+6)

We move all terms to the left:

-2(6u-5)+3u-(3(u+6))=0

We add all the numbers together, and all the variables

3u-2(6u-5)-(3(u+6))=0

We multiply parentheses

3u-12u-(3(u+6))+10=0



We calculate terms in parentheses: -(3(u+6)), so:

3(u+6)

We multiply parentheses

3u+18

Back to the equation:

-(3u+18)



We add all the numbers together, and all the variables

-9u-(3u+18)+10=0

We get rid of parentheses

-9u-3u-18+10=0

We add all the numbers together, and all the variables

-12u-8=0

We move all terms containing u to the left, all other terms to the right

-12u=8

u=8/-12

u=-2/3

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