-2(5z-5)=5(2-2z)

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Solution for -2(5z-5)=5(2-2z) equation:


Simplifying
-2(5z + -5) = 5(2 + -2z)

Reorder the terms:
-2(-5 + 5z) = 5(2 + -2z)
(-5 * -2 + 5z * -2) = 5(2 + -2z)
(10 + -10z) = 5(2 + -2z)
10 + -10z = (2 * 5 + -2z * 5)
10 + -10z = (10 + -10z)

Add '-10' to each side of the equation.
10 + -10 + -10z = 10 + -10 + -10z

Combine like terms: 10 + -10 = 0
0 + -10z = 10 + -10 + -10z
-10z = 10 + -10 + -10z

Combine like terms: 10 + -10 = 0
-10z = 0 + -10z
-10z = -10z

Add '10z' to each side of the equation.
-10z + 10z = -10z + 10z

Combine like terms: -10z + 10z = 0
0 = -10z + 10z

Combine like terms: -10z + 10z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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