-2(5w-1)+3w=4+4(2w-2)

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Solution for -2(5w-1)+3w=4+4(2w-2) equation: 



-2(5w-1)+3w=4+4(2w-2)

We move all terms to the left:

-2(5w-1)+3w-(4+4(2w-2))=0

We add all the numbers together, and all the variables

3w-2(5w-1)-(4+4(2w-2))=0

We multiply parentheses

3w-10w-(4+4(2w-2))+2=0



We calculate terms in parentheses: -(4+4(2w-2)), so:

4+4(2w-2)

determiningTheFunctionDomain
4(2w-2)+4

We multiply parentheses

8w-8+4

We add all the numbers together, and all the variables

8w-4

Back to the equation:

-(8w-4)



We add all the numbers together, and all the variables

-7w-(8w-4)+2=0

We get rid of parentheses

-7w-8w+4+2=0

We add all the numbers together, and all the variables

-15w+6=0

We move all terms containing w to the left, all other terms to the right

-15w=-6

w=-6/-15

w=2/5

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