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-2(5-3x)-(1-x)=2(x-4)
We move all terms to the left:
-2(5-3x)-(1-x)-(2(x-4))=0
We add all the numbers together, and all the variables
-2(-3x+5)-(-1x+1)-(2(x-4))=0
We multiply parentheses
6x-(-1x+1)-(2(x-4))-10=0
We get rid of parentheses
6x+1x-(2(x-4))-1-10=0
We calculate terms in parentheses: -(2(x-4)), so:We add all the numbers together, and all the variables
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
7x-(2x-8)-11=0
We get rid of parentheses
7x-2x+8-11=0
We add all the numbers together, and all the variables
5x-3=0
We move all terms containing x to the left, all other terms to the right
5x=3
x=3/5
x=3/5
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