-2(4y-3)-8y+6=4(y-3)

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Solution for -2(4y-3)-8y+6=4(y-3) equation: 



-2(4y-3)-8y+6=4(y-3)

We move all terms to the left:

-2(4y-3)-8y+6-(4(y-3))=0

We add all the numbers together, and all the variables

-8y-2(4y-3)-(4(y-3))+6=0

We multiply parentheses

-8y-8y-(4(y-3))+6+6=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

-16y-(4y-12)+12=0

We get rid of parentheses

-16y-4y+12+12=0

We add all the numbers together, and all the variables

-20y+24=0

We move all terms containing y to the left, all other terms to the right

-20y=-24

y=-24/-20

y=1+1/5

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