-2(4y-3)-8y+6=(y-2)

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Solution for -2(4y-3)-8y+6=(y-2) equation: 



-2(4y-3)-8y+6=(y-2)

We move all terms to the left:

-2(4y-3)-8y+6-((y-2))=0

We add all the numbers together, and all the variables

-8y-2(4y-3)-((y-2))+6=0

We multiply parentheses

-8y-8y-((y-2))+6+6=0



We calculate terms in parentheses: -((y-2)), so:

(y-2)

We get rid of parentheses

y-2

Back to the equation:

-(y-2)



We add all the numbers together, and all the variables

-16y-(y-2)+12=0

We get rid of parentheses

-16y-y+2+12=0

We add all the numbers together, and all the variables

-17y+14=0

We move all terms containing y to the left, all other terms to the right

-17y=-14

y=-14/-17

y=14/17

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