-2(4x-3)+8x=4+4(2x-2)

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Solution for -2(4x-3)+8x=4+4(2x-2) equation: 



-2(4x-3)+8x=4+4(2x-2)

We move all terms to the left:

-2(4x-3)+8x-(4+4(2x-2))=0

We add all the numbers together, and all the variables

8x-2(4x-3)-(4+4(2x-2))=0

We multiply parentheses

8x-8x-(4+4(2x-2))+6=0



We calculate terms in parentheses: -(4+4(2x-2)), so:

4+4(2x-2)

determiningTheFunctionDomain
4(2x-2)+4

We multiply parentheses

8x-8+4

We add all the numbers together, and all the variables

8x-4

Back to the equation:

-(8x-4)



We add all the numbers together, and all the variables

-(8x-4)+6=0

We get rid of parentheses

-8x+4+6=0

We add all the numbers together, and all the variables

-8x+10=0

We move all terms containing x to the left, all other terms to the right

-8x=-10

x=-10/-8

x=1+1/4

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