-2(4u-3)+7u=5(u+4)

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Solution for -2(4u-3)+7u=5(u+4) equation: 



-2(4u-3)+7u=5(u+4)

We move all terms to the left:

-2(4u-3)+7u-(5(u+4))=0

We add all the numbers together, and all the variables

7u-2(4u-3)-(5(u+4))=0

We multiply parentheses

7u-8u-(5(u+4))+6=0



We calculate terms in parentheses: -(5(u+4)), so:

5(u+4)

We multiply parentheses

5u+20

Back to the equation:

-(5u+20)



We add all the numbers together, and all the variables

-1u-(5u+20)+6=0

We get rid of parentheses

-1u-5u-20+6=0

We add all the numbers together, and all the variables

-6u-14=0

We move all terms containing u to the left, all other terms to the right

-6u=14

u=14/-6

u=-2+1/3

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