-2(4b-3)=-10+8(-2b+10)

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Solution for -2(4b-3)=-10+8(-2b+10) equation: 



-2(4b-3)=-10+8(-2b+10)

We move all terms to the left:

-2(4b-3)-(-10+8(-2b+10))=0

We multiply parentheses

-8b-(-10+8(-2b+10))+6=0



We calculate terms in parentheses: -(-10+8(-2b+10)), so:

-10+8(-2b+10)

determiningTheFunctionDomain
8(-2b+10)-10

We multiply parentheses

-16b+80-10

We add all the numbers together, and all the variables

-16b+70

Back to the equation:

-(-16b+70)



We get rid of parentheses

-8b+16b-70+6=0

We add all the numbers together, and all the variables

8b-64=0

We move all terms containing b to the left, all other terms to the right

8b=64

b=64/8

b=8

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