-2(4+5v)(-2)=(-22)-4v

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Solution for -2(4+5v)(-2)=(-22)-4v equation: 



-2(4+5v)(-2)=(-22)-4v

We move all terms to the left:

-2(4+5v)(-2)-((-22)-4v)=0

We add all the numbers together, and all the variables

-2(5v+4)(-2)-((-22)-4v)=0

We multiply parentheses ..

-2(-10v-8)-((-22)-4v)=0



We calculate terms in parentheses: -((-22)-4v), so:

(-22)-4v

determiningTheFunctionDomain
-4v+(-22)

We add all the numbers together, and all the variables

-4v-22

Back to the equation:

-(-4v-22)



We multiply parentheses

20v-(-4v-22)+16=0

We get rid of parentheses

20v+4v+22+16=0

We add all the numbers together, and all the variables

24v+38=0

We move all terms containing v to the left, all other terms to the right

24v=-38

v=-38/24

v=-1+7/12

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