-2(4+3y)=2+(4+y)

Solution for -2(4+3y)=2+(4+y) equation:

-2(4+3y)=2+(4+y)

We move all terms to the left:

-2(4+3y)-(2+(4+y))=0

We add all the numbers together, and all the variables

-2(3y+4)-(2+(y+4))=0

We multiply parentheses

-6y-(2+(y+4))-8=0


We calculate terms in parentheses: -(2+(y+4)), so:

2+(y+4)

determiningTheFunctionDomain
(y+4)+2

We get rid of parentheses

y+4+2

We add all the numbers together, and all the variables

y+6

Back to the equation:

-(y+6)


We get rid of parentheses

-6y-y-6-8=0

We add all the numbers together, and all the variables

-7y-14=0

We move all terms containing y to the left, all other terms to the right

-7y=14

y=14/-7

y=-2