-2(3y-9)-y=-4(y-5)

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Solution for -2(3y-9)-y=-4(y-5) equation: 



-2(3y-9)-y=-4(y-5)

We move all terms to the left:

-2(3y-9)-y-(-4(y-5))=0

We add all the numbers together, and all the variables

-1y-2(3y-9)-(-4(y-5))=0

We multiply parentheses

-1y-6y-(-4(y-5))+18=0



We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)



We add all the numbers together, and all the variables

-7y-(-4y+20)+18=0

We get rid of parentheses

-7y+4y-20+18=0

We add all the numbers together, and all the variables

-3y-2=0

We move all terms containing y to the left, all other terms to the right

-3y=2

y=2/-3

y=-2/3

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