-2(3y-4)-y=-3(y-4)

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Solution for -2(3y-4)-y=-3(y-4) equation: 



-2(3y-4)-y=-3(y-4)

We move all terms to the left:

-2(3y-4)-y-(-3(y-4))=0

We add all the numbers together, and all the variables

-1y-2(3y-4)-(-3(y-4))=0

We multiply parentheses

-1y-6y-(-3(y-4))+8=0



We calculate terms in parentheses: -(-3(y-4)), so:

-3(y-4)

We multiply parentheses

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

-7y-(-3y+12)+8=0

We get rid of parentheses

-7y+3y-12+8=0

We add all the numbers together, and all the variables

-4y-4=0

We move all terms containing y to the left, all other terms to the right

-4y=4

y=4/-4

y=-1

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