-2(3y-4)-y=-2(y-2)

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Solution for -2(3y-4)-y=-2(y-2) equation: 



-2(3y-4)-y=-2(y-2)

We move all terms to the left:

-2(3y-4)-y-(-2(y-2))=0

We add all the numbers together, and all the variables

-1y-2(3y-4)-(-2(y-2))=0

We multiply parentheses

-1y-6y-(-2(y-2))+8=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We add all the numbers together, and all the variables

-7y-(-2y+4)+8=0

We get rid of parentheses

-7y+2y-4+8=0

We add all the numbers together, and all the variables

-5y+4=0

We move all terms containing y to the left, all other terms to the right

-5y=-4

y=-4/-5

y=4/5

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