-2(3y-4)+30y=8(4+3y)-18

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Solution for -2(3y-4)+30y=8(4+3y)-18 equation: 



-2(3y-4)+30y=8(4+3y)-18

We move all terms to the left:

-2(3y-4)+30y-(8(4+3y)-18)=0

We add all the numbers together, and all the variables

-2(3y-4)+30y-(8(3y+4)-18)=0

We add all the numbers together, and all the variables

30y-2(3y-4)-(8(3y+4)-18)=0

We multiply parentheses

30y-6y-(8(3y+4)-18)+8=0



We calculate terms in parentheses: -(8(3y+4)-18), so:

8(3y+4)-18

We multiply parentheses

24y+32-18

We add all the numbers together, and all the variables

24y+14

Back to the equation:

-(24y+14)



We add all the numbers together, and all the variables

24y-(24y+14)+8=0

We get rid of parentheses

24y-24y-14+8=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation

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