-2(3y-3)+y=5(y+4)

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Solution for -2(3y-3)+y=5(y+4) equation: 



-2(3y-3)+y=5(y+4)

We move all terms to the left:

-2(3y-3)+y-(5(y+4))=0

We add all the numbers together, and all the variables

y-2(3y-3)-(5(y+4))=0

We multiply parentheses

y-6y-(5(y+4))+6=0



We calculate terms in parentheses: -(5(y+4)), so:

5(y+4)

We multiply parentheses

5y+20

Back to the equation:

-(5y+20)



We add all the numbers together, and all the variables

-5y-(5y+20)+6=0

We get rid of parentheses

-5y-5y-20+6=0

We add all the numbers together, and all the variables

-10y-14=0

We move all terms containing y to the left, all other terms to the right

-10y=14

y=14/-10

y=-1+2/5

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