-2(3y-1)+4y=6+2(6y-1)

Solution for -2(3y-1)+4y=6+2(6y-1) equation:

-2(3y-1)+4y=6+2(6y-1)

We move all terms to the left:

-2(3y-1)+4y-(6+2(6y-1))=0

We add all the numbers together, and all the variables

4y-2(3y-1)-(6+2(6y-1))=0

We multiply parentheses

4y-6y-(6+2(6y-1))+2=0


We calculate terms in parentheses: -(6+2(6y-1)), so:

6+2(6y-1)

determiningTheFunctionDomain
2(6y-1)+6

We multiply parentheses

12y-2+6

We add all the numbers together, and all the variables

12y+4

Back to the equation:

-(12y+4)


We add all the numbers together, and all the variables

-2y-(12y+4)+2=0

We get rid of parentheses

-2y-12y-4+2=0

We add all the numbers together, and all the variables

-14y-2=0

We move all terms containing y to the left, all other terms to the right

-14y=2

y=2/-14

y=-1/7