-2(3x-6)+8x=3(5-x)-18

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Solution for -2(3x-6)+8x=3(5-x)-18 equation: 



-2(3x-6)+8x=3(5-x)-18

We move all terms to the left:

-2(3x-6)+8x-(3(5-x)-18)=0

We add all the numbers together, and all the variables

-2(3x-6)+8x-(3(-1x+5)-18)=0

We add all the numbers together, and all the variables

8x-2(3x-6)-(3(-1x+5)-18)=0

We multiply parentheses

8x-6x-(3(-1x+5)-18)+12=0



We calculate terms in parentheses: -(3(-1x+5)-18), so:

3(-1x+5)-18

We multiply parentheses

-3x+15-18

We add all the numbers together, and all the variables

-3x-3

Back to the equation:

-(-3x-3)



We add all the numbers together, and all the variables

2x-(-3x-3)+12=0

We get rid of parentheses

2x+3x+3+12=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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