-2(3x-5)=(x+3)+8

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Solution for -2(3x-5)=(x+3)+8 equation: 



-2(3x-5)=(x+3)+8

We move all terms to the left:

-2(3x-5)-((x+3)+8)=0

We multiply parentheses

-6x-((x+3)+8)+10=0



We calculate terms in parentheses: -((x+3)+8), so:

(x+3)+8

We get rid of parentheses

x+3+8

We add all the numbers together, and all the variables

x+11

Back to the equation:

-(x+11)



We get rid of parentheses

-6x-x-11+10=0

We add all the numbers together, and all the variables

-7x-1=0

We move all terms containing x to the left, all other terms to the right

-7x=1

x=1/-7

x=-1/7

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