-2(3x-4)+4x=6(x+2)

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Solution for -2(3x-4)+4x=6(x+2) equation: 



-2(3x-4)+4x=6(x+2)

We move all terms to the left:

-2(3x-4)+4x-(6(x+2))=0

We add all the numbers together, and all the variables

4x-2(3x-4)-(6(x+2))=0

We multiply parentheses

4x-6x-(6(x+2))+8=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We add all the numbers together, and all the variables

-2x-(6x+12)+8=0

We get rid of parentheses

-2x-6x-12+8=0

We add all the numbers together, and all the variables

-8x-4=0

We move all terms containing x to the left, all other terms to the right

-8x=4

x=4/-8

x=-1/2

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