-2(3a-5)=4(a+3)+8

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Solution for -2(3a-5)=4(a+3)+8 equation: 



-2(3a-5)=4(a+3)+8

We move all terms to the left:

-2(3a-5)-(4(a+3)+8)=0

We multiply parentheses

-6a-(4(a+3)+8)+10=0



We calculate terms in parentheses: -(4(a+3)+8), so:

4(a+3)+8

We multiply parentheses

4a+12+8

We add all the numbers together, and all the variables

4a+20

Back to the equation:

-(4a+20)



We get rid of parentheses

-6a-4a-20+10=0

We add all the numbers together, and all the variables

-10a-10=0

We move all terms containing a to the left, all other terms to the right

-10a=10

a=10/-10

a=-1

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