-2(3a-5)=4(a+10)

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Solution for -2(3a-5)=4(a+10) equation: 



-2(3a-5)=4(a+10)

We move all terms to the left:

-2(3a-5)-(4(a+10))=0

We multiply parentheses

-6a-(4(a+10))+10=0



We calculate terms in parentheses: -(4(a+10)), so:

4(a+10)

We multiply parentheses

4a+40

Back to the equation:

-(4a+40)



We get rid of parentheses

-6a-4a-40+10=0

We add all the numbers together, and all the variables

-10a-30=0

We move all terms containing a to the left, all other terms to the right

-10a=30

a=30/-10

a=-3

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