-2(3a-1)+24=4(a+1)-10+6a

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Solution for -2(3a-1)+24=4(a+1)-10+6a equation: 



-2(3a-1)+24=4(a+1)-10+6a

We move all terms to the left:

-2(3a-1)+24-(4(a+1)-10+6a)=0

We multiply parentheses

-6a-(4(a+1)-10+6a)+2+24=0



We calculate terms in parentheses: -(4(a+1)-10+6a), so:

4(a+1)-10+6a

determiningTheFunctionDomain
4(a+1)+6a-10

We add all the numbers together, and all the variables

6a+4(a+1)-10

We multiply parentheses

6a+4a+4-10

We add all the numbers together, and all the variables

10a-6

Back to the equation:

-(10a-6)



We add all the numbers together, and all the variables

-6a-(10a-6)+26=0

We get rid of parentheses

-6a-10a+6+26=0

We add all the numbers together, and all the variables

-16a+32=0

We move all terms containing a to the left, all other terms to the right

-16a=-32

a=-32/-16

a=+2

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