-2(3a+3)=4(2a-5)

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Solution for -2(3a+3)=4(2a-5) equation:



-2(3a+3)=4(2a-5)
We move all terms to the left:
-2(3a+3)-(4(2a-5))=0
We multiply parentheses
-6a-(4(2a-5))-6=0
We calculate terms in parentheses: -(4(2a-5)), so:
4(2a-5)
We multiply parentheses
8a-20
Back to the equation:
-(8a-20)
We get rid of parentheses
-6a-8a+20-6=0
We add all the numbers together, and all the variables
-14a+14=0
We move all terms containing a to the left, all other terms to the right
-14a=-14
a=-14/-14
a=1

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