-2(2y/4)=3(y-12)

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Solution for -2(2y/4)=3(y-12) equation:



-2(2y/4)=3(y-12)
We move all terms to the left:
-2(2y/4)-(3(y-12))=0
We add all the numbers together, and all the variables
-2(+2y/4)-(3(y-12))=0
We multiply parentheses
-4y-(3(y-12))=0
We calculate terms in parentheses: -(3(y-12)), so:
3(y-12)
We multiply parentheses
3y-36
Back to the equation:
-(3y-36)
We get rid of parentheses
-4y-3y+36=0
We add all the numbers together, and all the variables
-7y+36=0
We move all terms containing y to the left, all other terms to the right
-7y=-36
y=-36/-7
y=5+1/7

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