-2(2y-6)+2y=4(y+5)

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Solution for -2(2y-6)+2y=4(y+5) equation: 



-2(2y-6)+2y=4(y+5)

We move all terms to the left:

-2(2y-6)+2y-(4(y+5))=0

We add all the numbers together, and all the variables

2y-2(2y-6)-(4(y+5))=0

We multiply parentheses

2y-4y-(4(y+5))+12=0



We calculate terms in parentheses: -(4(y+5)), so:

4(y+5)

We multiply parentheses

4y+20

Back to the equation:

-(4y+20)



We add all the numbers together, and all the variables

-2y-(4y+20)+12=0

We get rid of parentheses

-2y-4y-20+12=0

We add all the numbers together, and all the variables

-6y-8=0

We move all terms containing y to the left, all other terms to the right

-6y=8

y=8/-6

y=-1+1/3

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