-2(2y-2)-y=-4(y-5)

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Solution for -2(2y-2)-y=-4(y-5) equation: 



-2(2y-2)-y=-4(y-5)

We move all terms to the left:

-2(2y-2)-y-(-4(y-5))=0

We add all the numbers together, and all the variables

-1y-2(2y-2)-(-4(y-5))=0

We multiply parentheses

-1y-4y-(-4(y-5))+4=0



We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)



We add all the numbers together, and all the variables

-5y-(-4y+20)+4=0

We get rid of parentheses

-5y+4y-20+4=0

We add all the numbers together, and all the variables

-1y-16=0

We move all terms containing y to the left, all other terms to the right

-y=16

y=16/-1

y=-16

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