-2(2y-1)=4y-(y+2)

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Solution for -2(2y-1)=4y-(y+2) equation: 



-2(2y-1)=4y-(y+2)

We move all terms to the left:

-2(2y-1)-(4y-(y+2))=0

We multiply parentheses

-4y-(4y-(y+2))+2=0



We calculate terms in parentheses: -(4y-(y+2)), so:

4y-(y+2)

We get rid of parentheses

4y-y-2

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We get rid of parentheses

-4y-3y+2+2=0

We add all the numbers together, and all the variables

-7y+4=0

We move all terms containing y to the left, all other terms to the right

-7y=-4

y=-4/-7

y=4/7

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