-2(2x-4)=3(2x+16)

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Solution for -2(2x-4)=3(2x+16) equation: 



-2(2x-4)=3(2x+16)

We move all terms to the left:

-2(2x-4)-(3(2x+16))=0

We multiply parentheses

-4x-(3(2x+16))+8=0



We calculate terms in parentheses: -(3(2x+16)), so:

3(2x+16)

We multiply parentheses

6x+48

Back to the equation:

-(6x+48)



We get rid of parentheses

-4x-6x-48+8=0

We add all the numbers together, and all the variables

-10x-40=0

We move all terms containing x to the left, all other terms to the right

-10x=40

x=40/-10

x=-4

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