-2(2x-4)-8=-3(4x+4)-3

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Solution for -2(2x-4)-8=-3(4x+4)-3 equation: 



-2(2x-4)-8=-3(4x+4)-3

We move all terms to the left:

-2(2x-4)-8-(-3(4x+4)-3)=0

We multiply parentheses

-4x-(-3(4x+4)-3)+8-8=0



We calculate terms in parentheses: -(-3(4x+4)-3), so:

-3(4x+4)-3

We multiply parentheses

-12x-12-3

We add all the numbers together, and all the variables

-12x-15

Back to the equation:

-(-12x-15)



We add all the numbers together, and all the variables

-4x-(-12x-15)=0

We get rid of parentheses

-4x+12x+15=0

We add all the numbers together, and all the variables

8x+15=0

We move all terms containing x to the left, all other terms to the right

8x=-15

x=-15/8

x=-1+7/8

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