-2(2x-3)=3(x-1)+10

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Solution for -2(2x-3)=3(x-1)+10 equation: 



-2(2x-3)=3(x-1)+10

We move all terms to the left:

-2(2x-3)-(3(x-1)+10)=0

We multiply parentheses

-4x-(3(x-1)+10)+6=0



We calculate terms in parentheses: -(3(x-1)+10), so:

3(x-1)+10

We multiply parentheses

3x-3+10

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

-4x-3x-7+6=0

We add all the numbers together, and all the variables

-7x-1=0

We move all terms containing x to the left, all other terms to the right

-7x=1

x=1/-7

x=-1/7

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