-2(2x-2)+8x=6+4(3x-2)

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Solution for -2(2x-2)+8x=6+4(3x-2) equation: 



-2(2x-2)+8x=6+4(3x-2)

We move all terms to the left:

-2(2x-2)+8x-(6+4(3x-2))=0

We add all the numbers together, and all the variables

8x-2(2x-2)-(6+4(3x-2))=0

We multiply parentheses

8x-4x-(6+4(3x-2))+4=0



We calculate terms in parentheses: -(6+4(3x-2)), so:

6+4(3x-2)

determiningTheFunctionDomain
4(3x-2)+6

We multiply parentheses

12x-8+6

We add all the numbers together, and all the variables

12x-2

Back to the equation:

-(12x-2)



We add all the numbers together, and all the variables

4x-(12x-2)+4=0

We get rid of parentheses

4x-12x+2+4=0

We add all the numbers together, and all the variables

-8x+6=0

We move all terms containing x to the left, all other terms to the right

-8x=-6

x=-6/-8

x=3/4

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