-2(2x-1)=-2(3x-2)+8

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Solution for -2(2x-1)=-2(3x-2)+8 equation: 



-2(2x-1)=-2(3x-2)+8

We move all terms to the left:

-2(2x-1)-(-2(3x-2)+8)=0

We multiply parentheses

-4x-(-2(3x-2)+8)+2=0



We calculate terms in parentheses: -(-2(3x-2)+8), so:

-2(3x-2)+8

We multiply parentheses

-6x+4+8

We add all the numbers together, and all the variables

-6x+12

Back to the equation:

-(-6x+12)



We get rid of parentheses

-4x+6x-12+2=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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