-2(2m-4)=3(m+12)

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Solution for -2(2m-4)=3(m+12) equation: 



-2(2m-4)=3(m+12)

We move all terms to the left:

-2(2m-4)-(3(m+12))=0

We multiply parentheses

-4m-(3(m+12))+8=0



We calculate terms in parentheses: -(3(m+12)), so:

3(m+12)

We multiply parentheses

3m+36

Back to the equation:

-(3m+36)



We get rid of parentheses

-4m-3m-36+8=0

We add all the numbers together, and all the variables

-7m-28=0

We move all terms containing m to the left, all other terms to the right

-7m=28

m=28/-7

m=-4

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